Leetcode-Max area of longest diagnoal rectangle

3000 Maximum Area of Longest Diagonal Rectangle

1 Problem

Leetcode

example 1: Input: dimensions = [[9,3],[8,6]] Output: 48 Explanation: For index = 0, length = 9 and width = 3. Diagonal length = sqrt(9 * 9 + 3 * 3) = sqrt(90) ≈ 9.487. For index = 1, length = 8 and width = 6. Diagonal length = sqrt(8 * 8 + 6 * 6) = sqrt(100) = 10. So, the rectangle at index 1 has a greater diagonal length therefore we return area = 8 * 6 = 48.

example 2: Input: dimensions = [[3,4],[4,3]] Output: 12 Explanation: Length of diagonal is the same for both which is 5, so maximum area = 12.